UNB/ CS/ David Bremner/ teaching/ cs2613/ books/ mdn/ Guide/ Functions

Functions are one of the fundamental building blocks in JavaScript. A function in JavaScript is similar to a procedure—a set of statements that performs a task or calculates a value, but for a procedure to qualify as a function, it should take some input and return an output where there is some obvious relationship between the input and the output. To use a function, you must define it somewhere in the scope from which you wish to call it.

See also the exhaustive reference chapter about JavaScript functions to get to know the details.

Defining functions

Function declarations

A function definition (also called a function declaration, or function statement) consists of the function keyword, followed by:

For example, the following code defines a simple function named square:

function square(number) {
  return number * number;
}

The function square takes one parameter, called number. The function consists of one statement that says to return the parameter of the function (that is, number) multiplied by itself. The return statement specifies the value returned by the function, which is number * number.

Parameters are essentially passed to functions by value — so if the code within the body of a function assigns a completely new value to a parameter that was passed to the function, the change is not reflected globally or in the code which called that function.

When you pass an object as a parameter, if the function changes the object's properties, that change is visible outside the function, as shown in the following example:

function myFunc(theObject) {
  theObject.make = "Toyota";
}

const mycar = {
  make: "Honda",
  model: "Accord",
  year: 1998,
};

console.log(mycar.make); // "Honda"
myFunc(mycar);
console.log(mycar.make); // "Toyota"

When you pass an array as a parameter, if the function changes any of the array's values, that change is visible outside the function, as shown in the following example:

function myFunc(theArr) {
  theArr[0] = 30;
}

const arr = [45];

console.log(arr[0]); // 45
myFunc(arr);
console.log(arr[0]); // 30

Function expressions

While the function declaration above is syntactically a statement, functions can also be created by a function expression.

Such a function can be anonymous; it does not have to have a name. For example, the function square could have been defined as:

const square = function (number) {
  return number * number;
};

console.log(square(4)); // 16

However, a name can be provided with a function expression. Providing a name allows the function to refer to itself, and also makes it easier to identify the function in a debugger's stack traces:

const factorial = function fac(n) {
  return n < 2 ? 1 : n * fac(n - 1);
};

console.log(factorial(3)); // 6

Function expressions are convenient when passing a function as an argument to another function. The following example shows a map function that should receive a function as first argument and an array as second argument:

function map(f, a) {
  const result = new Array(a.length);
  for (let i = 0; i < a.length; i++) {
    result[i] = f(a[i]);
  }
  return result;
}

In the following code, the function receives a function defined by a function expression and executes it for every element of the array received as a second argument:

function map(f, a) {
  const result = new Array(a.length);
  for (let i = 0; i < a.length; i++) {
    result[i] = f(a[i]);
  }
  return result;
}

const cube = function (x) {
  return x * x * x;
};

const numbers = [0, 1, 2, 5, 10];
console.log(map(cube, numbers)); // [0, 1, 8, 125, 1000]

In JavaScript, a function can be defined based on a condition. For example, the following function definition defines myFunc only if num equals 0:

let myFunc;
if (num === 0) {
  myFunc = function (theObject) {
    theObject.make = "Toyota";
  };
}

In addition to defining functions as described here, you can also use the Function constructor to create functions from a string at runtime, much like eval().

A method is a function that is a property of an object. Read more about objects and methods in Working with objects.

Calling functions

Defining a function does not execute it. Defining it names the function and specifies what to do when the function is called.

Calling the function actually performs the specified actions with the indicated parameters. For example, if you define the function square, you could call it as follows:

square(5);

The preceding statement calls the function with an argument of 5. The function executes its statements and returns the value 25.

Functions must be in scope when they are called, but the function declaration can be hoisted (appear below the call in the code). The scope of a function declaration is the function in which it is declared (or the entire program, if it is declared at the top level).

The arguments of a function are not limited to strings and numbers. You can pass whole objects to a function. The showProps() function (defined in Working with objects) is an example of a function that takes an object as an argument.

A function can call itself. For example, here is a function that computes factorials recursively:

function factorial(n) {
  if (n === 0 || n === 1) {
    return 1;
  } else {
    return n * factorial(n - 1);
  }
}

You could then compute the factorials of 1 through 5 as follows:

console.log(factorial(1)); // 1
console.log(factorial(2)); // 2
console.log(factorial(3)); // 6
console.log(factorial(4)); // 24
console.log(factorial(5)); // 120

There are other ways to call functions. There are often cases where a function needs to be called dynamically, or the number of arguments to a function vary, or in which the context of the function call needs to be set to a specific object determined at runtime.

It turns out that functions are themselves objects — and in turn, these objects have methods. (See the Function object.) The call() and apply() methods can be used to achieve this goal.

Function hoisting

Consider the example below:

console.log(square(5)); // 25

function square(n) {
  return n * n;
}

This code runs without any error, despite the square() function being called before it's declared. This is because the JavaScript interpreter hoists the entire function declaration to the top of the current scope, so the code above is equivalent to:

// All function declarations are effectively at the top of the scope
function square(n) {
  return n * n;
}

console.log(square(5)); // 25

Function hoisting only works with function declarations — not with function expressions. The following code will not work:

console.log(square(5)); // ReferenceError: Cannot access 'square' before initialization
const square = function (n) {
  return n * n;
};

Function scope

Variables defined inside a function cannot be accessed from anywhere outside the function, because the variable is defined only in the scope of the function. However, a function can access all variables and functions defined inside the scope in which it is defined.

In other words, a function defined in the global scope can access all variables defined in the global scope. A function defined inside another function can also access all variables defined in its parent function, and any other variables to which the parent function has access.

// The following variables are defined in the global scope
const num1 = 20;
const num2 = 3;
const name = "Chamakh";

// This function is defined in the global scope
function multiply() {
  return num1 * num2;
}

console.log(multiply()); // 60

// A nested function example
function getScore() {
  const num1 = 2;
  const num2 = 3;

  function add() {
    return `${name} scored ${num1 + num2}`;
  }

  return add();
}

console.log(getScore()); // "Chamakh scored 5"

Scope and the function stack

Recursion

A function can refer to and call itself. There are three ways for a function to refer to itself:

  1. The function's name
  2. arguments.callee
  3. An in-scope variable that refers to the function

For example, consider the following function definition:

const foo = function bar() {
  // statements go here
};

Within the function body, the following are all equivalent:

  1. bar()
  2. arguments.callee()
  3. foo()

A function that calls itself is called a recursive function. In some ways, recursion is analogous to a loop. Both execute the same code multiple times, and both require a condition (to avoid an infinite loop, or rather, infinite recursion in this case).

For example, consider the following loop:

let x = 0;
// "x < 10" is the loop condition
while (x < 10) {
  // do stuff
  x++;
}

It can be converted into a recursive function declaration, followed by a call to that function:

function loop(x) {
  // "x >= 10" is the exit condition (equivalent to "!(x < 10)")
  if (x >= 10) {
    return;
  }
  // do stuff
  loop(x + 1); // the recursive call
}
loop(0);

However, some algorithms cannot be simple iterative loops. For example, getting all the nodes of a tree structure (such as the DOM) is easier via recursion:

function walkTree(node) {
  if (node === null) {
    return;
  }
  // do something with node
  for (let i = 0; i < node.childNodes.length; i++) {
    walkTree(node.childNodes[i]);
  }
}

Compared to the function loop, each recursive call itself makes many recursive calls here.

It is possible to convert any recursive algorithm to a non-recursive one, but the logic is often much more complex, and doing so requires the use of a stack.

In fact, recursion itself uses a stack: the function stack. The stack-like behavior can be seen in the following example:

function foo(i) {
  if (i < 0) {
    return;
  }
  console.log(`begin: ${i}`);
  foo(i - 1);
  console.log(`end: ${i}`);
}
foo(3);

// Logs:
// begin: 3
// begin: 2
// begin: 1
// begin: 0
// end: 0
// end: 1
// end: 2
// end: 3

Nested functions and closures

You may nest a function within another function. The nested (inner) function is private to its containing (outer) function.

It also forms a closure. A closure is an expression (most commonly, a function) that can have free variables together with an environment that binds those variables (that "closes" the expression).

Since a nested function is a closure, this means that a nested function can "inherit" the arguments and variables of its containing function. In other words, the inner function contains the scope of the outer function.

To summarize:

The following example shows nested functions:

function addSquares(a, b) {
  function square(x) {
    return x * x;
  }
  return square(a) + square(b);
}

console.log(addSquares(2, 3)); // 13
console.log(addSquares(3, 4)); // 25
console.log(addSquares(4, 5)); // 41

Since the inner function forms a closure, you can call the outer function and specify arguments for both the outer and inner function:

function outside(x) {
  function inside(y) {
    return x + y;
  }
  return inside;
}

const fnInside = outside(3); // Think of it like: give me a function that adds 3 to whatever you give it
console.log(fnInside(5)); // 8
console.log(outside(3)(5)); // 8

Preservation of variables

Notice how x is preserved when inside is returned. A closure must preserve the arguments and variables in all scopes it references. Since each call provides potentially different arguments, a new closure is created for each call to outside. The memory can be freed only when the returned inside is no longer accessible.

This is not different from storing references in other objects, but is often less obvious because one does not set the references directly and cannot inspect them.

Multiply-nested functions

Functions can be multiply-nested. For example:

Thus, the closures can contain multiple scopes; they recursively contain the scope of the functions containing it. This is called scope chaining. (The reason it is called "chaining" is explained later.)

Consider the following example:

function A(x) {
  function B(y) {
    function C(z) {
      console.log(x + y + z);
    }
    C(3);
  }
  B(2);
}
A(1); // Logs 6 (which is 1 + 2 + 3)

In this example, C accesses B's y and A's x.

This can be done because:

  1. B forms a closure including A (i.e., B can access A's arguments and variables).
  2. C forms a closure including B.
  3. Because C's closure includes B and B's closure includes A, then C's closure also includes A. This means C can access both B and A's arguments and variables. In other words, C chains the scopes of B and A, in that order.

The reverse, however, is not true. A cannot access C, because A cannot access any argument or variable of B, which C is a variable of. Thus, C remains private to only B.

Name conflicts

When two arguments or variables in the scopes of a closure have the same name, there is a name conflict. More nested scopes take precedence. So, the innermost scope takes the highest precedence, while the outermost scope takes the lowest. This is the scope chain. The first on the chain is the innermost scope, and the last is the outermost scope. Consider the following:

function outside() {
  const x = 5;
  function inside(x) {
    return x * 2;
  }
  return inside;
}

console.log(outside()(10)); // 20 (instead of 10)

The name conflict happens at the statement return x * 2 and is between inside's parameter x and outside's variable x. The scope chain here is {inside, outside, global object}. Therefore, inside's x takes precedences over outside's x, and 20 (inside's x) is returned instead of 10 (outside's x).

Closures

Closures are one of the most powerful features of JavaScript. JavaScript allows for the nesting of functions and grants the inner function full access to all the variables and functions defined inside the outer function (and all other variables and functions that the outer function has access to).

However, the outer function does not have access to the variables and functions defined inside the inner function. This provides a sort of encapsulation for the variables of the inner function.

Also, since the inner function has access to the scope of the outer function, the variables and functions defined in the outer function will live longer than the duration of the outer function execution, if the inner function manages to survive beyond the life of the outer function. A closure is created when the inner function is somehow made available to any scope outside the outer function.

// The outer function defines a variable called "name"
const pet = function (name) {
  const getName = function () {
    // The inner function has access to the "name" variable of the outer function
    return name;
  };
  return getName; // Return the inner function, thereby exposing it to outer scopes
};
const myPet = pet("Vivie");

console.log(myPet()); // "Vivie"

It can be much more complex than the code above. An object containing methods for manipulating the inner variables of the outer function can be returned.

const createPet = function (name) {
  let sex;

  const pet = {
    // setName(newName) is equivalent to setName: function (newName)
    // in this context
    setName(newName) {
      name = newName;
    },

    getName() {
      return name;
    },

    getSex() {
      return sex;
    },

    setSex(newSex) {
      if (
        typeof newSex === "string" &&
        (newSex.toLowerCase() === "male" || newSex.toLowerCase() === "female")
      ) {
        sex = newSex;
      }
    },
  };

  return pet;
};

const pet = createPet("Vivie");
console.log(pet.getName()); // Vivie

pet.setName("Oliver");
pet.setSex("male");
console.log(pet.getSex()); // male
console.log(pet.getName()); // Oliver

In the code above, the name variable of the outer function is accessible to the inner functions, and there is no other way to access the inner variables except through the inner functions. The inner variables of the inner functions act as safe stores for the outer arguments and variables. They hold "persistent" and "encapsulated" data for the inner functions to work with. The functions do not even have to be assigned to a variable, or have a name.

const getCode = (function () {
  const apiCode = "0]Eal(eh&2"; // A code we do not want outsiders to be able to modify…

  return function () {
    return apiCode;
  };
})();

console.log(getCode()); // "0]Eal(eh&2"

Note: There are a number of pitfalls to watch out for when using closures!

If an enclosed function defines a variable with the same name as a variable in the outer scope, then there is no way to refer to the variable in the outer scope again. (The inner scope variable "overrides" the outer one, until the program exits the inner scope. It can be thought of as a name conflict.)

const createPet = function (name) {
  // The outer function defines a variable called "name".
  return {
    setName(name) {
      // The enclosed function also defines a variable called "name".
      name = name; // How do we access the "name" defined by the outer function?
    },
  };
};

Using the arguments object

The arguments of a function are maintained in an array-like object. Within a function, you can address the arguments passed to it as follows:

arguments[i];

where i is the ordinal number of the argument, starting at 0. So, the first argument passed to a function would be arguments[0]. The total number of arguments is indicated by arguments.length.

Using the arguments object, you can call a function with more arguments than it is formally declared to accept. This is often useful if you don't know in advance how many arguments will be passed to the function. You can use arguments.length to determine the number of arguments actually passed to the function, and then access each argument using the arguments object.

For example, consider a function that concatenates several strings. The only formal argument for the function is a string that specifies the characters that separate the items to concatenate. The function is defined as follows:

function myConcat(separator) {
  let result = ""; // initialize list
  // iterate through arguments
  for (let i = 1; i < arguments.length; i++) {
    result += arguments[i] + separator;
  }
  return result;
}

You can pass any number of arguments to this function, and it concatenates each argument into a string "list":

console.log(myConcat(", ", "red", "orange", "blue"));
// "red, orange, blue, "

console.log(myConcat("; ", "elephant", "giraffe", "lion", "cheetah"));
// "elephant; giraffe; lion; cheetah; "

console.log(myConcat(". ", "sage", "basil", "oregano", "pepper", "parsley"));
// "sage. basil. oregano. pepper. parsley. "

Note: The arguments variable is "array-like", but not an array. It is array-like in that it has a numbered index and a length property. However, it does not possess all of the array-manipulation methods.

See the Function object in the JavaScript reference for more information.

Function parameters

There are two special kinds of parameter syntax: default parameters and rest parameters.

Default parameters

In JavaScript, parameters of functions default to undefined. However, in some situations it might be useful to set a different default value. This is exactly what default parameters do.

In the past, the general strategy for setting defaults was to test parameter values in the body of the function and assign a value if they are undefined.

In the following example, if no value is provided for b, its value would be undefined when evaluating a*b, and a call to multiply would normally have returned NaN. However, this is prevented by the second line in this example:

function multiply(a, b) {
  b = typeof b !== "undefined" ? b : 1;
  return a * b;
}

console.log(multiply(5)); // 5

With default parameters, a manual check in the function body is no longer necessary. You can put 1 as the default value for b in the function head:

function multiply(a, b = 1) {
  return a * b;
}

console.log(multiply(5)); // 5

For more details, see default parameters in the reference.

Rest parameters

The rest parameter syntax allows us to represent an indefinite number of arguments as an array.

In the following example, the function multiply uses rest parameters to collect arguments from the second one to the end. The function then multiplies these by the first argument.

function multiply(multiplier, ...theArgs) {
  return theArgs.map((x) => multiplier * x);
}

const arr = multiply(2, 1, 2, 3);
console.log(arr); // [2, 4, 6]

Arrow functions

An arrow function expression (also called a fat arrow to distinguish from a hypothetical -> syntax in future JavaScript) has a shorter syntax compared to function expressions and does not have its own this, arguments, super, or new.target. Arrow functions are always anonymous.

Two factors influenced the introduction of arrow functions: shorter functions and non-binding of this.

Shorter functions

In some functional patterns, shorter functions are welcome. Compare:

const a = ["Hydrogen", "Helium", "Lithium", "Beryllium"];

const a2 = a.map(function (s) {
  return s.length;
});

console.log(a2); // [8, 6, 7, 9]

const a3 = a.map((s) => s.length);

console.log(a3); // [8, 6, 7, 9]

No separate this

Until arrow functions, every new function defined its own this value (a new object in the case of a constructor, undefined in strict mode function calls, the base object if the function is called as an "object method", etc.). This proved to be less than ideal with an object-oriented style of programming.

function Person() {
  // The Person() constructor defines `this` as itself.
  this.age = 0;

  setInterval(function growUp() {
    // In nonstrict mode, the growUp() function defines `this`
    // as the global object, which is different from the `this`
    // defined by the Person() constructor.
    this.age++;
  }, 1000);
}

const p = new Person();

In ECMAScript 3/5, this issue was fixed by assigning the value in this to a variable that could be closed over.

function Person() {
  // Some choose `that` instead of `self`.
  // Choose one and be consistent.
  const self = this;
  self.age = 0;

  setInterval(function growUp() {
    // The callback refers to the `self` variable of which
    // the value is the expected object.
    self.age++;
  }, 1000);
}

Alternatively, a bound function could be created so that the proper this value would be passed to the growUp() function.

An arrow function does not have its own this; the this value of the enclosing execution context is used. Thus, in the following code, the this within the function that is passed to setInterval has the same value as this in the enclosing function:

function Person() {
  this.age = 0;

  setInterval(() => {
    this.age++; // `this` properly refers to the person object
  }, 1000);
}

const p = new Person();